A 220 V DC shunt motor has an armature resistance of 0.5 Ω. If the full load armature current is 20 A, what is the induced EMF?

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MPPGCL JE Electrical 28 April 2023 Shift 3 Official Paper
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  1. 210 V
  2. 220 V
  3. 230 V
  4. 240 V

Answer (Detailed Solution Below)

Option 1 : 210 V
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Detailed Solution

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Concept

The induced EMF in a DC shunt motor is given by:

\(E_b=V_t-I_aR_a\)

where, Eb = Induced EMF

Vt = Terminal voltage

Ia = Armature current

Ra = Armature resistance

Calculation

Given, Vt = 220 V

Ia = 20 A

Ra = 0.5 Ω

\(E_b=220-(20\times 0.5)\)

Eb = 210 V

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