A memory chip has a capacity of 4 kB. How many address lines are required?

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RRB JE ECE 22 Apr 2025 Shift 1 CBT 2 Official Paper
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  1. 10
  2. 12
  3. 16
  4. 14

Answer (Detailed Solution Below)

Option 2 : 12
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Explanation:

A memory chip has a capacity of 4 kB. To determine the number of address lines required, we need to understand the relationship between memory capacity and address lines. The capacity of a memory chip is the product of the number of addressable memory locations and the size of each memory location.

Firstly, 4 kB (kilobytes) needs to be converted into bytes. Since 1 kB = 1024 bytes, we have:

4 kB = 4 × 1024 bytes = 4096 bytes

Each memory location in a typical memory chip stores 1 byte of data. Therefore, the memory chip with a capacity of 4096 bytes has 4096 addressable memory locations.

The number of address lines required (n) can be determined using the formula:

Number of addressable memory locations = 2n

Setting this equal to the number of memory locations we have:

2n = 4096

To solve for n, we take the logarithm base 2 of both sides:

n = log2(4096)

Since 4096 is a power of 2 (specifically, 212), we have:

n = 12

Therefore, 12 address lines are required to address 4096 memory locations.

Hence, the correct answer is option 2, which is 12.

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