A plane slab of 100 mm thickness generates heat. It is observed that the temperature drop between the centre and its surface to be 50°C . If the thickness is increased to 20 cm the temperature difference will be

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ESE Mechanical 2013 Official Paper - 1
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  1. 100°C
  2. 200°C
  3. 400°C
  4. 600°C

Answer (Detailed Solution Below)

Option 2 : 200°C
Free
ST 1: UPSC ESE (IES) Civil - Building Materials
20 Qs. 40 Marks 24 Mins

Detailed Solution

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Concept:

Plane wall with uniform heat generation:

For one dimensional steady state condition

Here at x = -L, T = Tω ,x = L, T = Tω

Calculation:

Initial thickness = 2L1 = 100 mm;

Final thickness = 2L2 = 20 cm = 200 mm;

(T - T1)max = 50°C;

From the above relation,

Substituting the values of L1 and L2, we get 

(T - T2)max = 4 × (T - T1)max 

⇒ (T - T2)max = 200°C

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