A power supply has a full load voltage of 24 V. It's no load voltage for 5% regulation is :

This question was previously asked in
MPPKVVCL Jabalpur JE Electrical 16 August 2018 Official Paper
View all MPPGCL Junior Engineer Papers >
  1. 29 V
  2. 25.2 V
  3. 22.8 V
  4. 19 V

Answer (Detailed Solution Below)

Option 2 : 25.2 V
Free
MPPGCL JE Electrical Fundamentals Mock Test
20 Qs. 20 Marks 24 Mins

Detailed Solution

Download Solution PDF

The correct answer is option 2):(25.2 V)

Concept:

The percentage regulation is defined as:

VNL = No load voltage

VFL = Full load voltage

Calculation:

VNL = 25.2 V

Latest MPPGCL Junior Engineer Updates

Last updated on Jul 18, 2025

-> MPPGCL Junior Engineer Notification 2025 has been released for various fields of post (Advt No. 3233).

-> MPPGCL has announced a total of 90 vacancies for Civil, Mechanical, Electrical, and Electronics Engineering (Junior Engineer).

->  Interested candidates can submit their online application form, from 23rd July to 21st August 2025. 

-> MPPGCL Junior Engineer result PDF has been released at the offiical website.

-> The MPPGCL Junior Engineer Exam Date has been announced.

-> The MPPGCL Junior Engineer Notification was released for 284 vacancies.

-> The selection process includes a Computer Based Test and Document Verification.

-> Candidates can check the MPPGCL JE Previous Year Papers which helps to understand the difficulty level of the exam.

More Steady State Analysis of Transmission Analysis Questions

Hot Links: teen patti vungo teen patti real cash lucky teen patti