A starts from a point at a speed of 34 m/s. After 5 seconds, B starts chasing A from the same point at a speed of 44 m/s. What will be the distance travelled by B before A is caught by B?

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SSC CGL 2022 Tier-I Official Paper (Held On : 07 Dec 2022 Shift 3)
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  1. 748 metres
  2. 862 metres
  3. 675 metres
  4. 549 metres

Answer (Detailed Solution Below)

Option 1 : 748 metres
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PYST 1: SSC CGL - General Awareness (Held On : 20 April 2022 Shift 2)
25 Qs. 50 Marks 10 Mins

Detailed Solution

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Given:

Speed of A = 34 m/s

Speed of B = 44 m/s

Formula Used:

Relative speed in one direction = Speed1 -Speed2

Calculations:

⇒ Distance covered by A in 5 seconds = 34 × 5 = 170 m

⇒ Relative Speed of B w.r.t. A = (44 - 34) m/s = 10 m/s

Now, taking A to be at rest, B has to cover 170 m to catch A

⇒ Time taken by B to catch A = 170 / 10 =17 seconds

⇒ Total distance covered by B = 17 × 44 = 748 m 

⇒ Hence, The correct option is 1

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