Ajay rolled two dice together. What is the probability that first dice showed a multiple of 3 and the second dice showed an even number?

  1. \(\frac{1}{6}\)
  2. \(\frac{1}{3}\)
  3. \(\frac{5}{6}\)
  4. \(\frac{1}{9}\)

Answer (Detailed Solution Below)

Option 1 : \(\frac{1}{6}\)
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Detailed Solution

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GIVEN:

One dice shows a multiple of 3.

Other dice shows even number.

CONCEPT:

Total number of outcomes in two dice is 36.

FORMULA USED:

P = Favorable outcomes/Total outcomes 

CALCULATION:
There are only 6 such cases as required,

(3,2), (3,4) (3,6) (6,2) (6,4) (6,6)

∴ Required probability = 6/36 = 1/6

∴ The probability is 1/6.

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