Question
Download Solution PDFFind the 51st term of the following series:
12, 13\(\frac{1}{2}\), 15, 16\(\frac{1}{2}\),18,... ...
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept used:
• A series is called an arithmetic progression (A.P.) when a sequence of numbers that has a fixed common difference between any two consecutive numbers.
• nth term of an AP = a + (n - 1) × d [ where, a = 1st term, d = common difference ]
Calculation:
According to the series, 12, 13\(\frac{1}{2}\), 15...
(2nd term - 1st term) = 1.5 = (3rd term - 2nd term), so the series is an AP
Now, 51st term = 12 + (51 - 1) × 1.5 = 87
∴ The correct answer is 87
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