Find the mean proportion between \(\left( {6 + \sqrt 8 } \right)\) and \(\left( {3 - \sqrt 2 } \right)\).

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SSC CGL 2022 Tier-I Official Paper (Held On : 03 Dec 2022 Shift 2)
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  1. \(2\sqrt {12} \)
  2. \(\sqrt {14} \)
  3. \(\left( {6 - \sqrt 8 } \right)\)
  4. \(\sqrt {15} \) - 7

Answer (Detailed Solution Below)

Option 2 : \(\sqrt {14} \)
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Detailed Solution

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Concept used:

Mean proportion of a and b = \(\sqrt {ab} \)

Calculation:

\(\sqrt{\left( {6 + \sqrt 8 } \right)\left( {3 - \sqrt 2 } \right)}\)

⇒ \(\sqrt{18-6\sqrt2+3\sqrt8-\sqrt{16}}\)

⇒ \(\sqrt{18-6\sqrt2+6\sqrt2-4}\)

⇒ \(\sqrt{18-4}\)

⇒ \(\sqrt {14} \)

∴ The required answer is \(\sqrt {14} \).

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