Find the number that when successively divided by 5, 7 and 9 leaves the reminders 2, 0 and 2, respectively, and the last quotient is 15.

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MPPGCL JE Electrical 28 April 2023 Shift 3 Official Paper
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  1. 4797
  2. 4977
  3. 4597
  4. 4687

Answer (Detailed Solution Below)

Option 1 : 4797
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Detailed Solution

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Given:

Dividers: 5, 7, 9

Remainders: 2, 0, 2

Last quotient: 15

Formula used:

Dividend = (Divisor × Quotient) + Remainder

Calculations:

Third division: 9 × 15 + 2 = 137

Second division: 7 × 137 + 0 = 959

First division: 5 × 959 + 2 = 4797

∴ The number is 4797.

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