Question
Download Solution PDFFind the number that when successively divided by 5, 7 and 9 leaves the reminders 2, 0 and 2, respectively, and the last quotient is 15.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Dividers: 5, 7, 9
Remainders: 2, 0, 2
Last quotient: 15
Formula used:
Dividend = (Divisor × Quotient) + Remainder
Calculations:
Third division: 9 × 15 + 2 = 137
Second division: 7 × 137 + 0 = 959
First division: 5 × 959 + 2 = 4797
∴ The number is 4797.
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