Question
Download Solution PDFFind the odd one in terms of units.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
To find the odd one in terms of units, we need to analyze the dimensional units of each expression involving:
- L (Inductance): unit is henry (H) → \( [L] = \frac{V·s}{A} \)
- R (Resistance): unit is ohm (Ω) → \( [R] = \frac{V}{A} \)
- C (Capacitance): unit is farad (F) → \( [C] = \frac{A·s}{V} \)
Analyzing each option:
- \(\frac{L}{R}\)
Units: \(\frac{H}{\Omega} = \frac{V·s/A}{V/A} = s\)
This has units of seconds (time).
- RC
Units: \(\Omega·F = \left(\frac{V}{A}\right)\left(\frac{A·s}{V}\right) = s\)
This also has units of seconds (time).
- \(\sqrt{LC}\)
Units: \(\sqrt{H·F} = \sqrt{\left(\frac{V·s}{A}\right)\left(\frac{A·s}{V}\right)} = \sqrt{s^2} = s\)
This also has units of seconds (time).
- \(\frac{1}{\sqrt{LC}}\)
Units: \(\frac{1}{\sqrt{H·F}} = \frac{1}{\sqrt{s^2}} = \frac{1}{s}\)
This has units of 1/seconds (frequency).
Conclusion:
Options 1, 2, and 3 all have the same unit: seconds (s), meaning they represent time constants or durations.
Option 4 has units of 1/second (Hz), representing frequency — so it is dimensionally different.
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