For the impedance Z = 3 + j4, what is the value of admittance?

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SSC JE Electrical 14 Nov 2022 Shift 3 Official Paper
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  1. Y = 0.12 − j0.16
  2. Y = 3 + j4
  3. Y = 0.12 + j0.16
  4. Y = 0

Answer (Detailed Solution Below)

Option 1 : Y = 0.12 − j0.16
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Detailed Solution

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Concept

The relationship between impedance and admittance is given by:

\(Y={1\over Z}\)

where, Y = Admittance

Z = Impedance

Calculation

Given, Z = 3 + j4

\(Y={1\over 3+j4}\times {3-j4\over 3-j4}\)

\(Y={3-j4\over (3)^2\space +(4)^2}\)

\(Y={3-j4\over 25}\)

Y = 0.12 − j0.16

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