Question
Download Solution PDFA और B एक कार्य को क्रमशः 25 दिनों और 18 दिनों में कर सकते हैं। A अकेले 4 दिन कार्य करता है और छोड़ देता है। शेष कार्य को पूरा करने के लिए B को कितने दिनों की आवश्यकता होगी?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
A कार्य को 25 दिनों में कर सकता है
B कार्य को 18 दिनों में कर सकता है
A, 4 दिन कार्य करता है और छोड़ देता है
गणना:
मान लीजिए कुल कार्य = 25 और 18 का LCM = 450 इकाई
A की दर = 450 ÷ 25 = 18 इकाई/दिन
B की दर = 450 ÷ 18 = 25 इकाई/दिन
⇒ A द्वारा 4 दिनों में किया गया कार्य = 4 × 18 = 72 इकाई
⇒ शेष कार्य = 450 − 72 = 378 इकाई
⇒ B के लिए समय = 378 ÷ 25 = 15\(\frac{3}{25}\) दिन
∴ B को कार्य पूरा करने में 15\(\frac{3}{25}\) दिन लगेंगे।
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