Question
Download Solution PDFकिसी दिए गए बिंदु पर पृथ्वी का चुंबकीय क्षेत्र 0.5 × 10-5 Wbm-2 है। इस क्षेत्र को 5.0 सेमी त्रिज्या के एक वृत्ताकार चालक पाश के केंद्र में चुंबकीय प्रेरण द्वारा निरस्त किया जाना है। पाश में प्रवाहित होने के लिए आवश्यक धारा लगभग है:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है, एक बिंदु पर पृथ्वी का चुंबकीय क्षेत्र
BE = 0.5 × 10-5 Wbm-2
एक वृत्ताकार वलय की त्रिज्या, r = 5 cm
इसलिए, 5 सेमी त्रिज्या के वृत्ताकार चालक पाश के केंद्र में चुंबकीय प्रेरण द्वारा क्षेत्र को निरस्त करने के लिए, फिर BE = BR [वलय केंद्र पर चुंबकीय क्षेत्र]
i = 0.4A
Last updated on Jun 19, 2025
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