Question
Download Solution PDFएक त्रिभुज की तीन भुजाओं की लम्बाई (सेमी में) क्रमशः 48, 55 और 73 है। सबसे लम्बी भुजा के मध्य-बिंदु को उसके सम्मुख शीर्ष से मिलाने वाली माध्यिका की लम्बाई (सेमी में) कितनी है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
एक त्रिभुज की तीन भुजाओं की लम्बाई (सेमी में) क्रमशः 48, 55 और 73 हैं।
प्रयुक्त अवधारणा:
एक समकोण त्रिभुज की माध्यिका = H/2
यहाँ,
H = कर्ण
गणना:
482 + 552
⇒ 2304 + 3025
⇒ 5329
⇒ 732
इसलिए, त्रिभुज एक समकोण त्रिभुज है।
इसलिए, माध्यिका = h/2 = 73/2
⇒ 36.5
∴ अभीष्ट उत्तर 36.5 सेमी है।
Last updated on Jul 8, 2025
-> The SSC CGL Notification 2025 for the Combined Graduate Level Examination has been officially released on the SSC's new portal – www.ssc.gov.in.
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.
-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> The CSIR NET Exam Schedule 2025 has been released on its official website.