sec2 54° - cot2 36° +  sin2 37° × sec2 53° +  tan 60° का मान कितना है?

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SSC CGL 2023 Tier-I Official Paper (Held On: 14 Jul 2023 Shift 2)
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Answer (Detailed Solution Below)

Option 2 :
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SSC CGL Tier 1 2025 Full Test - 01
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Detailed Solution

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प्रयुक्त अवधारणा:

tan(90° - θ) = cot θ 

cot (90° - θ) = tan θ 

sec (90° - θ) = cosec θ 

cosec2θ - cot2θ = 1 

sec2θ - tan2θ = 1 

गणना :

sec2 54° - cot2 36° +  sin2 37° × sec2 53° +  tan 60°

⇒ sec2 54° - cot2 (90° - 54°) +  sin2 37° × sec2 (90° - 37°) +  tan 60°

⇒ sec2 54° - tan2 54° +  sin2 37° × cosec2 37° +  tan 60°

⇒ 1 + 3/2 + 2 

⇒ 9/2

व्यंजक का मान 9/2 है।

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