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If a circuit load impedance is (25 - j25), find the power factor. 

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HPCL Engineer Electrical 01 Nov 2022 Official Paper
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  1. 1
  2. 0
  3. 0.707
  4. 0.5

Answer (Detailed Solution Below)

Option 3 : 0.707
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Detailed Solution

Download Solution PDF

The correct answer is option 3):(0.707)

Concept:

The load impedance is given by: Z = R + j X (for lagging load)

Z = R - j X (for leading load)

Calculation:

Given

A circuit load impedance is (25 - j25) Ω 

= 

= 0.707

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