Question
Download Solution PDFIn a race of 500 meters, Q can give a head start of 50 meters to P and R can give a head start of 100 meters to Q to complete the race at the same time. Find the head start that R can give to P to complete this race at the same time.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFData:
Race length = 500m,
Q can give a head start of 50m to P,
R can give a head start of 100m to Q.
Concept:
In a race, if two competitors finish at the same time and one has a head start, the one without the head start is faster. This can be extrapolated to calculate head starts between different pairs of competitors.
Solution:
R's speed relative to Q's speed = 500/400 = 1.25,
R's speed relative to P's speed = 1.25 × (500/450) = 1.3889,
Head start R can give P = 500 - (500/1.3889) = 140m.
Therefore, R can give a head start of 140 meters to P to complete the race at the same time.
Last updated on Jul 8, 2025
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