Question
Download Solution PDFIn nine games, A wins five games with score differences of 12, 3, 8, 4 and 1, while in the remaining four games, he loses with score differences of –4, –1, –2 and –3. The average score difference of A in all the nine games is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
A wins five games with score differences of 12, 3, 8, 4, and 1.
A loses four games with score differences of -4, -1, -2, and -3.
Formula Used:
Average score difference = Total score difference / Number of games
Calculation:
Total score difference = 12 + 3 + 8 + 4 + 1 - 4 - 1 - 2 - 3
⇒ Total score difference = 18
Number of games = 9
Average score difference = Total score difference / Number of games
⇒ Average score difference = 18 / 9
⇒ Average score difference = 2
The average score difference of A in all the nine games is 2.
Last updated on Jul 15, 2025
-> SSC Selection Phase 13 Exam Dates have been announced on 15th July 2025.
-> The SSC Phase 13 CBT Exam is scheduled for 24th, 25th, 26th, 28th, 29th, 30th, 31st July and 1st August, 2025.
-> The Staff Selection Commission had officially released the SSC Selection Post Phase 13 Notification 2025 on its official website at ssc.gov.in.
-> A total number of 2423 Vacancies have been announced for various selection posts under Government of India.
-> The SSC Selection Post Phase 13 exam is conducted for recruitment to posts of Matriculation, Higher Secondary, and Graduate Levels.
-> The selection process includes a CBT and Document Verification.
-> Some of the posts offered through this exam include Laboratory Assistant, Deputy Ranger, Upper Division Clerk (UDC), and more.
-> Enhance your exam preparation with the SSC Selection Post Previous Year Papers & SSC Selection Post Mock Tests for practice & revision.