Question
Download Solution PDF18 V च्या बॅटरीवर काम करणारा लाइट बल्बमधून 3 A चा विद्युत् प्रवाह वाहतो. बल्बचा प्रतिरोध किती असेल?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFयोग्य उत्तर 6 Ω आहे.
Key Points
बल्बच्या प्रतिकाराची गणना करण्यासाठी आपण ओहमचा नियम वापरू शकतो:
ओहमचा नियम सांगतो की दोन बिंदूंमधील वाहकाद्वारे विद्युत् प्रवाह (I) दोन बिंदूंमधील विद्युतदाब (V) च्या थेट प्रमाणात आणि त्यांच्यामधील प्रतिरोध (R) च्या व्यस्त प्रमाणात आहे:
I = V/R
R = V/I
येथे:
R = ओहममध्ये प्रतिकार (Ω)
V = व्होल्टमधील विद्युतदाब (V)
I = अँपिअरमध्ये विद्युत् प्रवाह (A)
विद्युतदाब (V) 18 V आहे आणि विद्युतप्रवाह (I) 3 A आहे हे लक्षात घेऊन, आपण प्रतिरोध (R) शोधण्यासाठी समीकरणामध्ये ही मूल्ये बदलू शकतो:
R = V/I
⇒ 18 V / 3 A = 6 Ω
म्हणून, बल्बचा प्रतिरोध 6 ohms (Ω) आहे.
Last updated on Jul 21, 2025
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