\(0.13\overline {241} \) ला \(\frac{p}{q}\) रूपात लिहा, जेथे p आणि q हे पूर्णांक आणि q \( \ne \) 0 आहे.

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RRB Group D 26 Aug 2022 Shift 3 Official Paper
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  1. \(\frac{{3807}}{{24975}}\)
  2. \(\frac{{3287}}{{21780}}\)
  3. \(\frac{{3337}}{{24160}}\)
  4. \(\frac{{3307}}{{24975}}\)

Answer (Detailed Solution Below)

Option 4 : \(\frac{{3307}}{{24975}}\)
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RRB Group D Full Test 1
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Detailed Solution

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दिलेल्याप्रमाणे:

मूल्य =  \(0.13\overline {241} \) = 0.13241241241......

गणना:

समजा, x = \(0.13\overline {241} \) ........... (1)

समीकरण (1) ला 100 ने गुणा, आपल्याला मिळेल (कारण दोन अंक आहेत ज्यांवर बार नाही)

100x = 13.241241...... (2)

समीकरण (2) ला 1000 ने गुणा, आपल्याला मिळेल ( कारण तेथे तीन अंक आहेत ज्यांवर बार आहे)

100000x = 13241.241241....... (3)

आता समीकरण (2) समीकरण (3) ने वजा करा, आपल्याला मिळेल

99900x = 13228

x = \(\frac{13228}{99900}\)

x चे मूल्य सोपे करून, आपल्याला x = \(\frac{{3307}}{{24975}}\) मिळेल.

म्हणून, योग्य उत्तर \(\frac{{3307}}{{24975}}\) आहे.

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