Question
Download Solution PDFपाया त्रिज्या 12.6 सेमी आणि उंची 4 मीटर असलेल्या वृत्तचितीकार लोखंडी कंटेनरचे वजन शोधा, जेथे 1 सेमी3 लोखंडाचे वजन 2 ग्रॅम आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
पायाची त्रिज्या (r) = 12.6 सेमी
उंची (h) = 4 मीटर
लोखंडाचे 1 सेमी³ वजन = 2 ग्रॅम
सूत्र:
घनफळ (V) = πr²h
गणना:
उंची मीटर ते सेंटीमीटरमध्ये रूपांतरित करा:
उंची (h) = 4 मीटर x 100 सेमी/मीटर = 400 सेमी
आता, वृत्तचितीकार लोखंडी कंटेनरचे घनफळ मोजा:
V = π x (12.6 सेमी)² x 400 सेमी = 2 x 63504 सेमी³ = 199584 सेमी³
आता, वृत्तचितीकार लोखंडी कंटेनरचे वजन मोजा:
वजन = घनफळ x वजन प्रति सेमी³
वजन = 199584 सेमी³ x 2 ग्रॅम/सेमी³ = 399168 ग्रॅम
ग्रॅमचे किलोग्रॅममध्ये रूपांतर करा (1 किलो = 1000 ग्रॅम)
वजन = 399168 ग्रॅम / 1000 = 399.168 किलो
म्हणून, वृत्तचितीकार लोखंडी कंटेनरचे योग्य वजन अंदाजे 399.168 किलो आहे.
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