Question
Download Solution PDFABC त्रिकोणाचा मध्यक AD तयार होतो आणि त्यावर लंब CF टाकला जातो. BE AD ला लंब आहे. BC = 34 सेमी आणि DF = 8 सेमी असल्यास, BE ची लांबी (सेमी मध्ये) किती आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिले:
BC = 34 सेमी
DF = 8 सेमी
वापरलेले सूत्र:
त्रिकोणामध्ये, मध्यक बाजूस दुभाजक करतो.
गणना:
दिलेले BC = 34 सेमी
BED आणि CDF त्रिकोणामध्ये
BD = CD (कारण AD मध्य आहे)
∠E = ∠F
∠ BDE = ∠CDF (अनुलंब विरुद्ध कोन)
म्हणून त्रिकोण BED आणि CDF एकरूप आहेत
म्हणून, BE = CF
त्रिकोणी बेडमध्ये:
(BD) 2 = (BE) 2 + (ED) 2
⇒ (17) 2 = (BE) 2 + (8) 2
⇒ २८९ = ६४ + (BE ) २
⇒ (BE ) 2 = 289 - 64
⇒ BE = \(\sqrt(225)\)
⇒ BE = 15 सेमी
अशा प्रकारे, BE ची लांबी 15 सें.मी.
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