एक 8 Ω आणि दुसरा 24 Ω असे दोन रोध समांतर जोडणीत जोडलेले आहेत. हे संयोजन 14 Ω रोधक आणि 12 V विद्युतघटासह एकसर जोडणीत जोडलेले आहे. तर 8 Ω रोधामधून जाणारी विद्युतधारा काढा:

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RRB ALP Electrician 22 Jan 2019 Official Paper (Shift 3)
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  1. 0.45 A
  2. 0.30 A
  3. 0.15 A
  4. 0.60 A

Answer (Detailed Solution Below)

Option 1 : 0.45 A
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संकल्पना:

  • ओहमचा नियम: यानुसार, सर्व भौतिक अवस्था आणि तापमान स्थिर असताना, एखाद्या वाहकामधील व्होल्टता ही त्यामधून प्रवाहित होणाऱ्या विद्युतधारेच्या समानुपाती असते.
  • गणितीयदृष्ट्या, विद्युतधारा-व्होल्टेज पुढीलप्रकारे लिहिले जाऊ शकते: V = IR, येथे V = व्होल्टता, I = विद्युतधारा, R = रोध
  • समांतर जोडणीतील समतुल्य रोधासाठी
  • एकसर जोडणीतील समतुल्य रोधासाठी

    • Req  = R1 + R2 + .... + Rn

  • ​विद्युतधारा विभागणी नियम:
    •  R1  रोधामधून वाहणारी विद्युतधारा, 
    • R2  रोधामधून वाहणारी विद्युतधारा, 

गणना:

दिलेले आहे, रोध, R1 = 8 Ω , R2 = 24 Ω, विद्युतघट, V = 12 व्होल्ट

रोध समांतर जोडणीत जोडलेले असताना,

समांतर जोडणीसाठी, 

RP = 6 Ω 

आता, रोध RP हा 14Ω रोधासह एकसर जोडणीत जोडलेला आहे,

Req = 6 + 14 = 20 Ω 

विद्युत परिपथामधील विद्युतधारा, 

8 Ω रोधामधून वाहणारी विद्युतधारा पुढीलप्रकारे,

म्हणून, 8 Ω रोधामधून वाहणारी विद्युतधारा 0.45 A आहे.

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