Question
Download Solution PDFPie-chart I shows the distribution of students who appeared in Board examination from schools A, B, C, D and E and pie-chart II shows the distribution of students who passed the examination from these schools. Read both these pie-charts and answer the question :
The total number of students who failed from schools B and D is what percent of the total number of students who passed from schools A and C?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
Pie-chart I shows the distribution of students who appeared in Board examination from schools A, B, C, D and E.
Total number of Students appeared = 1800
School A appeared = 17% of 1800 = 0.17 × 1800 = 306
School B appeared = 18% of 1800 = 0.18 × 1800 = 324
School C appeared = 20% of 1800 = 0.20 × 1800 = 360
School D appeared = 21% of 1800 = 0.21 × 1800 = 378
School E appeared = 24% of 1800 = 0.24 × 1800 = 432
Pie-chart II shows the distribution of students who passed the examination from these schools.
Total number of Students passed = 1500
School A passed = 15% of 1500 = 0.15 × 1500 = 225
School B passed = 18% of 1500 = 0.18 × 1500 = 270
School C passed = 21% of 1500 = 0.21 × 1500 = 315
School D passed = 24% of 1500 = 0.24 × 1500 = 360
School E passed = 22% of 1500 = 0.22 × 1500 = 330
Number of failed students = Number of appeared students - Number of passed students
Students who failed from School B = Students appeared from B - Students passed from B
⇒ Failed from B = 324 - 270 = 54
Students who failed from School D = Students appeared from D - Students passed from D
⇒ Failed from D = 378 - 360 = 18
Total students who failed from schools B and D = Failed from B + Failed from D = 54 + 18 = 72
Total students who passed from schools A and C = Passed from A + Passed from C = 225 + 315 = 540
Required percentage =
⇒ Percentage = (72/540) × 100
⇒ Percentage = 720/54
⇒ Percentage = 40/3
⇒ Percentage =
∴ The correct answer is option 3.
Last updated on Jun 10, 2025
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