Question
Download Solution PDFPipe A can fill a tank in 12 minutes; pipe B can fill it in 18 minutes, while pipe C can empty the full tank in 36 minutes. If all the pipes are opened simultaneously, how much time will it take to fill the empty tank completely?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept used:
Efficiency = Total Work/ Total Time
Calculation:
Let the total capacity of the tank = 72 units [LCM of 12, 18 and 36]
According to the question
Efficiency of Pipe A = 72/12 = 6
Efficiency of Pipe B = 72/18 = 4
Efficiency of Pipe C = 72/36 = -2 (outlet pipe)
Combined efficiency of (A + B + C) = 6 + 4 + (-2) = 8
So, Time taken by (A + B + C) to fill the tank = 72/8 = 9 minutes
The answer is 9 minutes.
Last updated on Jul 7, 2025
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