Question
Download Solution PDFకుడి వృత్తాకార సిలెండర్ యొక్క ఘనపరిమాణం (సెం.మీ3.లో) 1 సె౦.మీ మరియు ఎత్తు 2 సె౦.మీ గా ఉంటుంది: (π = 22/7 తీసుకోండి)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFకుడి వృత్తాకార సిలెండర్ యొక్క ఘనపరిమాణం = πr2h
r = 1 సెం.మీ మరియు h = 2 సెం.మీ
∴ పరిమాణం = (22/7) × 1 × 2 = 44/7 సెం.మీ3
Last updated on Jul 19, 2025
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