Question
Download Solution PDFThe depth of root zone for a particular crop is 100 cm. If the dry unit weight of soil is 2.0 gm/cc of the field and its field capacity and permanent wilting point being 20% and 10% respectively, then the maximum storage capacity of irrigation water in cm will be
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
For an irrigation land:
SC = Saturation capacity, FC = Field capacity, OMC = Optimum moisture content, PWP = Permanent welting point and UWP = Ultimate welting point
1. Equivalent depth of water held at field capacity (x) = S × d × Fc
2. Equivalent depth of water held at PWP (x’) = S × d × (PWP)
3. Available moisture/storage capacity of soil (y) = S × d × (Fc - PWP)
4. Readily available moisture content (dw) = S × d × (Fc - OMC)
Given:
Field capacity (F. C) = 20 % = 0.20
Permanent willing point (PWP) = 10 % = 0.10
Depth of the root zone (d) = 100 cm
Dry Unit weight of soil (γd) = 2.0 g/cc
Calculations:
The storage capacity
The storage capacity
Hence, the storage capacity of the soil is 20 cm.
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