Question
Download Solution PDFComprehension
The following table shows the number of students who appeared in a Common Entrance Test (CET) from six different schools A-F during the years 2020-2022, and the ratio of number of passed (P) to the number of failed (F) students among them. Based on the data in the table, answer the questions:
School-wise Appearance of Students in CET during 2020-2022.
|
School |
2020 |
2021 |
2022 |
|||
|
Appeared |
P ∶ F |
Appeared |
P ∶ F |
Appeared |
P ∶ F |
|
|
A |
1292 |
11 ∶ 8 |
1508 |
7 ∶ 6 |
1344 |
3 ∶ 5 |
|
B |
1694 |
4 ∶ 7 |
1690 |
8 ∶ 5 |
1904 |
9 ∶ 8 |
|
C |
1620 |
8 ∶ 7 |
1584 |
7 ∶ 4 |
1274 |
4 ∶ 3 |
|
D |
1752 |
7 ∶ 5 |
1656 |
11 ∶ 7 |
1976 |
7 ∶ 12 |
|
E |
1740 |
3 ∶ 2 |
1452 |
7 ∶ 4 |
1430 |
8 ∶ 5 |
|
F |
1972 |
17 ∶ 12 |
1734 |
12 ∶ 5 |
1848 |
8 ∶ 13 |
The number of students who passed in the test from School E in the year 2020 is __________ of the number of students who failed in the test from School A in the year 2021.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
The number of students who passed in the test from School E in the year 2020 = (3 ÷ 5) × 1740 = 1044
Number of students who failed in the test from School A in the year 2021 = (6 ÷ 13) × 1508 = 696
Required Percentage = \(\dfrac{1044}{696} \) × 100 = 150%
∴ The number of students who passed in the test from School E in the year 2020 is 150% of the number of students who failed in the test from School A in the year 2021.
Last updated on Jul 6, 2025
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