Which two signs and two numbers should be interchanged to make the following equation correct?

840 ÷ 38 - 7 + 10 × 12 = 462

Given statement : 840 ÷ 38 - 7 + 10 × 12 = 462

According to the question, after interchanging the signs and numbers:

So,

• Option - (1) : 12 and 10, ÷ and +

840 ÷ 38 - 7 + 10 × 12 = 462 ⇒ 840 + 38 - 7 ÷ 12 × 10 = 462

840 + 38 - 0.58 × 10 = 462

840 + 38 - 5.8 = 462

878 - 5.8 = 462

872.2 ≠ 462 (LHS ≠ RHS)

• Option - (2) : 12 and 38, × and -

840 ÷ 38 - 7 + 10 × 12 = 462 ⇒ 840 ÷ 12 × 7 + 10 - 38 = 462

70 × 7 + 10 - 38 = 462

490 + 10 - 38 = 462

500 - 38 = 462

462 = 462 (LHS = RHS)

• Option - (3) : 12 and 7, + and ×

840 ÷ 38 - 7 + 10 × 12 = 462 ⇒ 840 ÷ 38 - 12 × 10 + 7 = 462

22.10 - 12 × 10 + 7 = 462

22.10 + 7 - 120 = 462

29.10 - 120 = 462

-90.9 ≠ 462 (LHS ≠ RHS)

• Option - (4) : 840 and 10, + and -

840 ÷ 38 - 7 + 10 × 12 = 462 ⇒ 10 ÷ 38 + 7 - 840 × 12 = 462

0.26 + 7 - 840 × 12 = 462

0.26 + 7 - 10080 = 462

7.26 - 10080 = 462

-10072.74 ≠ 462 (LHS ≠ RHS)