Question
Download Solution PDFA 100 kVA, 50 Hz single-phase transformer has ratio of secondary to primary turns as 0.1. The secondary voltage at no-load condition is 100 V. What is the value of primary voltage?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The transformation ratio in a transformer is
\(K = \frac{{{N_2}}}{{{N_1}}} = \frac{{{V_2}}}{{{V_1}}} = \frac{{{I_1}}}{{{I_2}}}\)
N2 = secondary turns
N1 = Primary turns
V1 = Primary Voltage
V2 = Secondary voltage
I1 = Primary current
I2 = Secondary current
Calculation:
Given
\(\frac{N_2}{N_1} = 0.1\)
V2 = 100 V
\(\frac{N_2}{N_1} = \frac{V_2}{V_1}\)
\(0.1 = \frac{100}{V_1}\)
V1 = 1000 V
Last updated on Jul 2, 2025
-> ESE Mains 2025 exam date has been released. As per the schedule, UPSC IES Mains exam 2025 will be conducted on August 10.
-> UPSC ESE result 2025 has been released. Candidates can download the ESE prelims result PDF from here.
-> UPSC ESE admit card 2025 for the prelims exam has been released.
-> The UPSC IES Prelims 2025 will be held on 8th June 2025.
-> The selection process includes a Prelims and a Mains Examination, followed by a Personality Test/Interview.
-> Candidates should attempt the UPSC IES mock tests to increase their efficiency. The UPSC IES previous year papers can be downloaded here.