Question
Download Solution PDFA billiard ball moving with a velocity 'v' collides on a rigid plate moving towards the ball with a velocity 'u'. If the elastic impact lasts for 't' seconds, then the mean elastic force acting on the ball is -
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is option 3) i.e. \(\frac{2m(v+u)}{t}\)
CONCEPT:
- Elastic collision: Elastic collision is a phenomenon where the collision of objects takes place such that the total linear momentum and kinetic energy of the system are conserved.
EXPLANATION:
- Since this is an elastic collision, linear momentum is said to be conserved.
As the ball moves forward and the plate moves towards it, the relative velocity of ball = v - (-u) = v + u
After the collision, the relative velocity of the ball = - (v+u) = -v - u
From Newton's second law of motion, \(F = \frac{m\Delta v}{t}\)
\(\Rightarrow F = \frac{m[(v+u )-(-v-u)]}{t}\)
\(\Rightarrow F = \frac{2m(v+u )}{t}\)
Last updated on Jul 4, 2025
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