Question
Download Solution PDFA bipolar junction transistor has common base current gain of 0.99 and collector base reverse saturation current of 1 μA. If it is operated with base current of 50 μA in common emitter configuration, what will be collector current?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Key Formula:
- Collector Current (IC) in common emitter configuration: IC = β × IB + ICBO
- Where:
- β = Current gain in common emitter configuration (related to α)
- IB = Base current
- ICBO = Collector-base reverse saturation current
Given Data:
- Common base current gain (α) = 0.99
- Collector-base reverse saturation current (ICBO) = 1 μA
- Base current (IB) = 50 μA
Step-by-Step Calculation:
1. Relation between α and β:
In a BJT, α and β are related as follows:
β = α / (1 - α)
Substitute the value of α:
β = 0.99 / (1 - 0.99)
β = 0.99 / 0.01 = 99
2. Collector Current (IC):
Using the formula:
IC = β × IB + ICBO
Substitute the values:
IC = 99 × 50 μA + 1 μA
IC = 4950 μA + 1 μA
IC = 4951 μA
Convert μA to mA:
IC = 4.951 mA
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