Question
Download Solution PDFA gas turbine plant working on Joule cycle produces 4000 kW of power. If its work ratio is 40%, what is the power consumed by the compressor in (kW)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Gas turbines operate on the Brayton cycle/Joule cycle. The Brayton cycle consists of four internally reversible processes:
- Isentropic compression (in a compressor)
- Constant-pressure heat addition
- Isentropic expansion (in a turbine)
- Constant-pressure heat rejection
Work ratio: Work ratio in the gas turbine is defined as the ratio of net-work to the turbine work.
The net-work in the turbine is given by Wturbine – Wcompressor, because the compressor is work consuming device therefore it consumes the work.
\(Work - ratio = \frac{{{{\rm{W}}_{{\rm{net}}}}}}{{{{\rm{W}}_{{\rm{turbine}}}}{\rm{\;}}}} = \;\frac{{{{\rm{W}}_{{\rm{turbine}}}}{\rm{\;}} - {\rm{\;}}{{\rm{W}}_{{\rm{compressor}}}}}}{{{{\rm{W}}_{{\rm{turbine}}}}}} = 1 - \;\frac{{{{\rm{W}}_{{\rm{compressor}}}}}}{{{{\rm{W}}_{{\rm{turbine}}}}}}\)
Calculation:
\(\begin{array}{l} 0.4 = \frac{{{W_{net}}}}{{{W_T}}} = \frac{{4000}}{{{W_T}}} \Rightarrow {W_T} = 10000~kW\\ \therefore {W_C} = {W_T} - {W_{net}} = 10000 - 4000 = 6000~kW \end{array}\)Last updated on Jul 2, 2025
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