Chord AB of a circle of radius 10 cm is at a distance 8 cm from the centre O. If tangents drawn at A and B intersect at P., then the length of the tangent AP (in cm) is:

This question was previously asked in
SSC CGL 2020 Tier-I Official Paper 10 (Held On : 18 Aug 2021 Shift 1)
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  1. 4
  2. 15
  3. 3.75
  4. 7.5

Answer (Detailed Solution Below)

Option 4 : 7.5
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Detailed Solution

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Given:

Radius = 10 cm

Concept used:

Concept of similarity

AAA similarity → If all three angles in one triangle are the same as the corresponding angles in the other, then the triangles are similar.

Calculation:

In, the given figure,

ΔDAO ∼ ΔAPO [∵ ∠OAP = ∠ODA = 90° and ∠AOD is common in two triangles]

So,

AD/AP = DO/AO

⇒ 6/AP = 8/10 [6, 8, 10 pythagoras triplets]

⇒ AP = 60/8

⇒ AP = 7.5 cm

∴ Length of tangent AP is 7.5 cm

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