Question
Download Solution PDFFind the missing number in the series given as:
4, 7, 11, 18, 29, 47, --, 123, 199.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFKey Points
Given,
4, 7, 11, 18, 29, 47, --, 123, 199.
To Find,
The missing number in the series.
Solution,
Given that,
A series
4, 7, 11, 18, 29, 47, -, 123, 199.
Here, one term is missing.
Let's take missing number = x
4, 7, 11, 18, 29, 47, x, 123, 199.
We need to find the relation of each term with each other.
By looking into the series, it's clear that
the third term is the sum of the preceding two numbers.
ie,
here, the third term
11 = 4+7 (preceding two terms)
Like that,
18 = 7+11
29 = 11 +18
47 = 29+18
So the missing number will be the sum of its preceding two numbers.
x = 29+47
x = 76.
Hence the number that is missing in the series is 76. Option(b) is correct.
Last updated on Jun 11, 2025
-> The UGC NET Exam Schedule 2025 for June has been released on its official website.
-> Check UPSC Prelims Result 2025, UPSC IFS Result 2025, UPSC Prelims Cutoff 2025, UPSC Prelims Result 2025 Name Wise & Rollno. Wise
-> The UGC NET Application Correction Window 2025 is available from 14th May to 15th May 2025.
-> The UGC NET 2025 online application form submission closed on 12th May 2025.
-> The June 2025 Exam will be conducted from 21st June to 30th June 2025
-> The UGC-NET exam takes place for 85 subjects, to determine the eligibility for 'Junior Research Fellowship’ and ‘Assistant Professor’ posts, as well as for PhD. admissions.
-> The exam is conducted bi-annually - in June and December cycles.
-> The exam comprises two papers - Paper I and Paper II. Paper I consists of 50 questions and Paper II consists of 100 questions.
-> The candidates who are preparing for the exam can check the UGC NET Previous Year Papers and UGC NET Test Series to boost their preparations.