Every element in the central column of the matrix has a simple arithmetic relationship with the pairs on the left and right in the corresponding row.

\(\left[\begin{array}{lllll} 17 & 12 & \mathbf{1} & 19 & 23 \\ 23 & 21 & \boldsymbol{X} & 18 & 20 \\ 24 & 17 & 3 & 32 & 36 \\ 35 & 28 & 2 & 19 & 24 \end{array}\right]\)

What would be the value of X?

The correct answer is 0

Explanation:

Given:

Every element in the central column of the matrix has a simple arithmetic relationship with the pairs on the left and right in the corresponding row.

The matrix is

Calculation:

We observe that the element in the central column (1, X, 3, 2) is the difference between the sums of the pairs on the left and right in the corresponding row.

For the first row:

(17 - 12) -  (23 - 19) = 5 - 4 = 1

For the third row:

(24 - 17) - (36 - 32) = 7 - 4 = 3

For the fourth row:

(35 - 28) - (24 - 19) = 7 - 5 = 2

Now, for the second row:

(23 - 21) - (20 - 18) = 2-2= 0

Therefore, the value of X should be 0