For two events R and S, let P(R) = 0.4, P(S) = p and P(R ∪ S) = 0.6. Then p equals

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  1. 0.2, when R and S are independent
  2. 0.2, when R and S are mutually disjoint
  3. Not determined in any case
  4. 0.2, when R and S are dependent

Answer (Detailed Solution Below)

Option 2 : 0.2, when R and S are mutually disjoint

Detailed Solution

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Concept:

P(R ∪ S) = P(R) + P(S) - P(R \(\cap\) S)

If R and S are mutually disjoint P(R \(\cap\) S) = 0

Calculation:

Given:

P(R) = 0.4, P(S) = p and P(R ∪ S) = 0.6

Let us assume R and S are mutually disjoint, then

P(R ∪ S) = P(R) + P(S) - P(R \(\cap\) S)

0.6 = 0.4 + p - 0

p = 0.2

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