Question
Download Solution PDFFor two events R and S, let P(R) = 0.4, P(S) = p and P(R ∪ S) = 0.6. Then p equals
- 0.2, when R and S are independent
- 0.2, when R and S are mutually disjoint
- Not determined in any case
- 0.2, when R and S are dependent
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
P(R ∪ S) = P(R) + P(S) - P(R \(\cap\) S)
If R and S are mutually disjoint P(R \(\cap\) S) = 0
Calculation:
Given:
P(R) = 0.4, P(S) = p and P(R ∪ S) = 0.6
Let us assume R and S are mutually disjoint, then
P(R ∪ S) = P(R) + P(S) - P(R \(\cap\) S)
0.6 = 0.4 + p - 0
p = 0.2
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