Question
Download Solution PDFएक कृष्णिका को 27°C और 927°C पर रखा जाता है I उत्सर्जित विकिरणों का अनुपात होगा -
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा:
स्टीफन-बोल्ट्जमैन नियम:
प्रति इकाई क्षेत्र प्रति सेकंड एक कृष्णिका द्वारा विकिरणित तापीय ऊर्जा निरपेक्ष तापमान के चतुर्थ घात के आनुपातिक होता है और निम्न द्वारा दिया जाता है:
E ∝ T4
E = σT4
σ = स्टीफन-बोल्ट्जमैन नियतांक = 5.67 × 10-8 W m-2K-4
गणना:
दिया गया है:
T1 = 27°C ⇒ 300 K और
T1 = 927°C ⇒ 1200 K
E = σT4
\(\frac{E_1}{E_2}=\frac{T_1^4}{T_2^4}\)
\(\frac{E_1}{E_2}=\frac{300^4}{1200^4}=\frac{1}{4^4}=\frac{1}{256}\)
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