एक कृष्णिका को 27°C और 927°C पर रखा जाता है I उत्सर्जित विकिरणों का अनुपात होगा -

This question was previously asked in
RPSC 2nd Grade Science - 2015 Official Paper
View all RPSC Senior Teacher Grade II Papers >
  1. 4
  2. 16
  3. 64
  4. 256

Answer (Detailed Solution Below)

Option 4 : 1  256
Free
RPSC Senior Grade II (Paper I): Full Test 1
5.1 K Users
100 Questions 200 Marks 120 Mins

Detailed Solution

Download Solution PDF

अवधारणा:

स्टीफन-बोल्ट्जमैन नियम:

प्रति इकाई क्षेत्र प्रति सेकंड एक कृष्णिका द्वारा विकिरणित तापीय ऊर्जा निरपेक्ष तापमान के चतुर्थ घात के आनुपातिक होता है और निम्न द्वारा दिया जाता है:

E ∝ T4

E = σT4

σ = स्टीफन-बोल्ट्जमैन नियतांक = 5.67 × 10-8 W m-2K-4

गणना:

दिया गया है:

T127°C ⇒ 300 K और

T1 = 927°C ⇒  1200 K

E = σT4

\(\frac{E_1}{E_2}=\frac{T_1^4}{T_2^4}\)

\(\frac{E_1}{E_2}=\frac{300^4}{1200^4}=\frac{1}{4^4}=\frac{1}{256}\)

Latest RPSC Senior Teacher Grade II Updates

Last updated on Jul 17, 2025

-> The latest RPSC Senior Teacher Notification 2025 notification has been released on 17th July 2025

-> A total of 6500 vacancies have been declared.

-> The applications can be submitted online between 19th August and 17th September 2025.

-> The written examination for RPSC Senior Teacher Grade 2 Recruitment (Secondary Ed. Dept.) will be communicated soon.

->The subjects for which the vacancies have been released are: Hindi, English, Sanskrit, Mathematics, Social Science, Urdu, Punjabi, Sindhi, Gujarati.

More Heat transfer Questions

More Thermal Properties of Matter Questions

Get Free Access Now
Hot Links: happy teen patti teen patti gold apk download teen patti bindaas teen patti real money app