BODMAS का उपयोग करके निम्नलिखित प्रश्न को सरल कीजिए।
1800 ÷ [10((12-6)+(24-12))]

This question was previously asked in
JKSSB SI Official Paper (Held On: 13 Dec 2022 Shift 1)
View all JKSSB Sub Inspector Papers >
  1. 15
  2. 8
  3. 12
  4. 10

Answer (Detailed Solution Below)

Option 4 : 10
Free
JKSSB SI GK Subject Test
3.9 K Users
20 Questions 40 Marks 20 Mins

Detailed Solution

Download Solution PDF

दिया गया:

1800 ÷ [10 × ((12 - 6) + (24 - 12))]

प्रयुक्त सूत्र:

BODMAS (कोष्ठक, का, भाग, गुणा, जोड़, घटाव)

गणनाएँ:

1800 ÷ [10 × ((12 - 6) + (24 - 12))]

⇒ 1800 ÷ [10 × (6 + 12)]

⇒ 1800 ÷ [10 × 18]

⇒ 1800 ÷ 180

⇒ 10

∴ उत्तर 10 है।

Latest JKSSB Sub Inspector Updates

Last updated on Jul 4, 2024

-> The JK Police SI applications process has started on 3rd December 2024. The last date to apply is 2nd January 2025.

-> JKSSB Sub Inspector Notification 2024 has been released for 669 vacancies.

-> Graduates between 18-28 years of age who are domiciled residents of Jammu & Kashmir are eligible for this post.

-> Candidates who will get the final selection will receive a JKSSB Sub Inspector Salary range between Rs. 35,700 to Rs. 1,13,100.

More Simplification Questions

Get Free Access Now
Hot Links: teen patti - 3patti cards game downloadable content teen patti list teen patti gold