If a circuit load impedance is (25 - j25), find the power factor.

Question

Question

This question was previously asked in

HPCL Engineer Electrical 01 Nov 2022 Official Paper

Answer 1

The correct answer is option 3):(0.707)

Concept:

The load impedance is given by: Z = R + j X (for lagging load)

Z = R - j X (for leading load)

F1 Savita Engineering 2-7-22 D33

\(cosϕ = {R \over Z}\)

Calculation:

Given

A circuit load impedance is (25 - j25) Ω

\(cosϕ = {R \over \sqrt{R^2+X^2}}\)

\(cosϕ = {25 \over \sqrt{(25)^2+(25)^2}}\)

= \(25 \over 35.35\)

= 0.707