If a current of 18.2 Ampere per second flows through a copper conductor and the average collision time of electrons is 0.25 μs, then the value of conductivity of the copper conductor is ______.

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  1. 0.80 × 106 mho/m
  2. 4.55 × 106​ mho/m
  3. 72.8 × 106​ mho/m
  4. 13.7 × 106​ mho/m

Answer (Detailed Solution Below)

Option 1 : 0.80 × 106 mho/m
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Detailed Solution

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Given:

\(\tau\text { collision time }=0.25\mu s=0.25\times10^{-6}s\)

\(ne=18.2\ A/sec\)

Concept:

Electrical Conductivity is given as

  • \(\sigma=\frac{ne^2\tau}{m}\)

where e is electronic charge \(e=1.6\times10^{-19}C\), m is mass of electron \(m=9.1\times10^{-31}kg\) 

Explanation:

Substitute all given values we get,

  • \(\sigma=\frac{ne^2\tau}{m}=\frac{18.2\times1.6\times10^{-19}\times0.25\times10^{-6}}{9.1\times10^{-31}}\)

 

  • \(\sigma=0.80\times10^6mho/m\)

 

Hence, the correct answer is Option-1-\(\sigma=0.80\times10^6mho/m\).

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