If the height of the cone is twice of the radius of its base circle then find the ratio of the area of base with total surface area:

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OPSC ASO (Maths & Reasoning) 27 Aug 2022 Official Paper
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  1. \(1:\sqrt{5} + 1\)
  2. \(​2:\sqrt{3}\)
  3. 3:2
  4. 4:3

Answer (Detailed Solution Below)

Option 1 : \(1:\sqrt{5} + 1\)
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Detailed Solution

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Given:

Height of cone = 2 × Radius of base circle.

Radius of base circle = r.

Total Surface Area (TSA) of cone = Area of base + Curved Surface Area.

Formula Used:

Area of base = πr2.

Curved Surface Area = πr × l, where l is the slant height.

Slant height (l) = √(r2 + h2).

Total Surface Area = πr2 + πr × l.

Ratio = Area of base / Total Surface Area.

Calculation:

Height (h) = 2r.

Slant height (l) = √(r2 + (2r)2)

⇒ l = √(r2 + 4r2)

⇒ l = √(5r2)

⇒ l = r√5.

Curved Surface Area = πr × r√5

⇒ Curved Surface Area = πr2√5.

Total Surface Area = πr2 + πr2√5.

⇒ Total Surface Area = πr2(1 + √5).

Area of base = πr2.

Ratio = Area of base / Total Surface Area

⇒ Ratio = πr2 / [πr2(1 + √5)]

⇒ Ratio = 1 / (1 + √5).

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