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If x/y=3/4 and 4x + 7y= 200, then find the value of y. 

This question was previously asked in
DSSSB Assistant Teacher (Nursery) Official Paper (Held On: 19 Nov, 2019 Shift 3)
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  1. 16
  2. 8
  3. 20
  4. 12

Answer (Detailed Solution Below)

Option 3 : 20
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Detailed Solution

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Calculation

Let x and y be 3a and 4a respectively.

4x + 7y= 200

12a + 28a = 200

40a = 200

a = 5

y = 4a → 4 × 5 = 20

The answer is 20.

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Latest DSSSB Nursery Teacher Updates

Last updated on Jul 9, 2025

-> The DSSSB Nursery Teacher Exam will be conducted from 10th to 14th August 2025.

-> The DSSSB Assistant Teacher (Nursery) Notification was released for 1455 vacancies.

-> Candidates who are 12th-passed and have Diploma/Certificate in Nursery Teacher Education or B. Ed.(Nursery) are eligible for this post.

-> The finally selected candidates for the post will receive a DSSSB Assistant Teacher Salary range between Rs. 35,400 to Rs. 1,12,400.

-> Candidates must refer to the DSSSB Assistant Teacher Previous Year Papers to boost their preparation.

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