In a steady flow reversible adiabatic process, work done is equal to: 

Explanation:

The first law of thermodynamics:

This law states that the heat and mechanical work are mutually convertible. According to this law, a definite amount of mechanical work is needed to produce a definite amount of heat and vice versa.

∴ From 1st Law of Thermodynamics,

• q = Δu + pdv for a closed system and,
• q = Δh - vdp for an open system 

and for a reversible adiabatic process q = 0, .i.e. Δh = vdp 

from Steady Flow Energy Equation S.F.E.E

\(\left( {{h_1} + \;\frac{{v_1^2}}{2} + g{z_1}} \right) + q =\;\left( {{h_2} + \frac{{v_2^2}}{2} + g{z_2}} \right) + w \)  

when potential and kinetic energy changes are zero or negligible,

h1 + q  = h2 + w 

given reversible adiabatic process so q = 0,

w = h1 - h2 = Δh

∴ In a steady flow reversible adiabatic process, work done is equal to change in enthalpy.