Question
Download Solution PDFIn the circuit shown in the figure, find the current flowing through the 8 Ω resistance-
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFKirchhoff's Current Law
According to Kirchhoff's Current Law, The total current entering a junction or a node is equal to the charge leaving the node. The algebraic sum of every current entering and leaving the node has to be zero.
Calculation
\({V-5\over 2}+{V\over 8}+{V+3\over 4}=0\)
\({4V-20+V+2V+6\over 8}=0\)
V = 2
The current through 8Ω is given by:
\(I={2\over 8}=0.25\space A\)
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