Question
Download Solution PDF28 सेमी त्रिज्या असलेल्या एका वर्तुळखंडाचे क्षेत्रफळ 112 सेमी2 आहे. तर वर्तुळखंडाच्या संबंधित कंसाची लांबी शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले आहे:
28 सेमी त्रिज्या असलेल्या एका वर्तुळखंडाचे क्षेत्रफळ 112 सेमी2 आहे.
गणना:
वर्तुळखंडाचे क्षेत्रफळ = πr²θ/360°
112 = π(28)²θ/360°
θ = 360/22
कंसाची लांबी = θ/360°(2πr)
⇒ 360/360 × 22/22 × 28/7 × 2
⇒ 8 सेमी
म्हणून, कंसाची लांबी 8 सेमी आहे.
Additional Information
वर्तुलखंडाचे क्षेत्रफळ = 1/2 × r × l
r = वर्तुळाची त्रिज्या
l = कंसाची लांबी
प्रश्नानुसार,
⇒ 112 = 1/2 × 28 × l
⇒ l = 8 सेमी
म्हणून, कंसाची लांबी 8 सेमी.
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