On heating [Mo(N2)2(PMe2Ph)4] and [ReCI(N2) (PMe2Ph)4], the products formed are respectively

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  1. [(η6-PhPMe2) Mo(PMe2Ph)3] and [(η-PhPMe2) Re(PMe2Ph)3]CI
  2. [(PMe2Ph)4Mo(μ-N2)2Mo (PMe2Ph)4] and [(PMe2Ph)4Re (μ-Cl)2Re (PMe2Ph)4]
  3. [(η6-PhPMe2)Mo (PMe2Ph)3] and [(PMe2Ph)4Re (μ-CI)2Re (PMe2Ph)4]
  4. [(PMe2Ph)4Mo(μ-N2)2Mo(PMe2Ph)4] and [(η-PhPMe2) Re(PMe2Ph)3]CI

Answer (Detailed Solution Below)

Option 3 : [(η6-PhPMe2)Mo (PMe2Ph)3] and [(PMe2Ph)4Re (μ-CI)2Re (PMe2Ph)4]
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Detailed Solution

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Concept:

EAN rule:

  • In organometallic compounds Effective atomic number (EAN) rule predicts the stability of binary metal carbonyls in which the metal atom is in a zero or low oxidation state. 
  • According to the EAN rule, thermodynamically stable transition metal organometallic complexes are formed when the sum of metal d electrons and electrons donated by the surrounding ligands are equaled to 18.
  • Dinitrogen (N2) is considered a two-electron donor species in organometallic complexes.    

Explanation:

  • The complex [Mo(N2)2(PMe2Ph)4] follows the 18-electron rule (EAN rule). The number of valence electrons contributed by a metal atom to the total electron count in a zero-oxidation state is equal to the group number.
  • In the complex [Mo(N2)2(PMe2Ph)4], Mo has a zero oxidation state and it belongs to group 6. So, Mo contributes 6 electrons. The two Dinitrogen (N2) contributes a total of 4 electrons and four PMe2Ph contributes a total of 8 electrons.
  • On heating the complex [Mo(N2)2(PMe2Ph)4] it results in removal of dinitrogen and forms the complex 

[(η6-PhPMe2)Mo (PMe2Ph)3].

  • The complex [(η6-PhPMe2)Mo (PMe2Ph)3] also obeys the EAN rule. One of the phenyl ring of the PMe2Ph ligand act as a 6-electron donor (\({\eta ^6}\)).
  • The complex [ReCI(N2) (PMe2Ph)4], also follows the 18-electron rule (EAN rule). On heating the complex [ReCI(N2) (PMe2Ph)4], it also results in the removal of dinitrogen and forms the complex, [(PMe2Ph)4Re (μ-Cl)2Re (PMe2Ph)4]. 
  • The product obeys the EAN rule as the two bridging Cl ligand contributes 3 electrons each to the metal centers.

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Conclusion:

  • On heating [Mo(N2)2(PMe2Ph)4] and [ReCI(N2) (PMe2Ph)4], the products formed are respectively, [(η6-PhPMe2)Mo (PMe2Ph)3] and [(PMe2Ph)4Re (μ-CI)2Re (PMe2Ph)4]. 
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