a + b + c = 14, ab + bc + ca = 47 మరియు abc = 15 అయితే 3 + b 3 +c 3 విలువను కనుగొనండి.

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NTPC CBT-I (Held On: 4 Jan 2021 Shift 2)
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  1. 815
  2. 825
  3. 835
  4. 845

Answer (Detailed Solution Below)

Option 1 : 815
Free
RRB NTPC Graduate Level Full Test - 01
100 Qs. 100 Marks 90 Mins

Detailed Solution

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ఇవ్వబడినది:

a + b + c = 14, ab + bc + ca = 47 మరియు abc = 15

ఉపయోగించవలసిన కాన్సెప్ట్:

a³ + b³ + c³ - 3abc = (a + b + c) × [(a + b + c)² -3(ab + bc + ca)]

గణన:

a³ + b³ + c³ - 3abc = 14 × [(14)² - 3 × 47]

⇒ a³ + b³ + c³ – 3 × 15 = 14(196 – 141)

⇒ a³ + b³ + c³ = 14(55) + 45

⇒ 770 + 45

⇒ 815

∴ సరైన సమాధానం ఎంపిక 1.

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