Question
Download Solution PDFO కేంద్రంగా గల వృత్తంలో, PQR అనేది ఆ వృత్తంపై Q బిందువు వద్ద ఒక స్పర్శరేఖగా ఉంటుంది. AB అనేది ∠BQR = 70° ఉన్న స్పర్శరేఖకు సమాంతరంగా ఉన్న వృత్తంలో ఒక చాపం. అయితే ∠AQB యొక్క కొలత ఎంత?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF⇒ ∠BQR = 70° (ఇచ్చింది)
⇒ ∠BQR = ∠QBA = 70° (ప్రత్యామ్నాయ అంతర్గతకోణము)
⇒ ∠BQR = ∠QAB = 70° (ప్రత్యామ్నాయ ఖండన సిద్దాంతం)
ΔAQB లో
⇒ ∠AQB + ∠QAB + ∠QBA = 180°
⇒ ∠AQB + 70° + 70° = 180°
⇒ ∠AQB = 180° – 140° = 40°
Last updated on Jul 11, 2025
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