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వ్యాసార్థం 28 సెం.మీ మరియు కేంద్ర కోణం 45° కలిగిన వృత్తం యొక్క వృత్తఖండం వైశాల్యం కనుగొనండి?

This question was previously asked in
Bihar STET TGT (Maths) Official Paper-I (Held On: 04 Sept, 2023 Shift 2)
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  1. 308 సెం.మీ2
  2. 294 సెం.మీ2
  3. 322 సెం.మీ2
  4. 318 సెం.మీ2

Answer (Detailed Solution Below)

Option 1 : 308 సెం.మీ2
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ఉపయోగించిన భావన:

వృత్తం యొక్క వృత్తఖండం వైశాల్యం: θ/ 360° × πr2, ఇక్కడ r అనేది వృత్తం యొక్క వ్యాసార్థం

వివరణ:

వృత్తం యొక్క వృత్తఖండం వైశాల్యం: θ/ 360° × πr2 = 45°/360° × 22/7 × 28 × 28 = 308సెం.మీ2, ఇక్కడ r అనేది వృత్తం యొక్క వ్యాసార్థం

కాబట్టి, సరైన సమాధానం 308 సెం.మీ2.

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